# Chapter 6 batch data processing with array

Example 6.1 assign 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 to ten elements in turn, and output in reverse order

```#include<stdio.h>
int main()
{
int i,a[10];
for(i=0;i<=9;i++)
scanf("%d",&a[i]);
for(i=9;1>=0;i--)
printf("%d",a[i]);
return 0;
}
```

Example 6.2 use array to process Fibonacci sequence

```#include<stdio.h>
int main()
{
int a[20]={1,1};
int i;
for(i=2;i<20;i++)
a[i]=a[i-2]+a[i-1];
for(i=0;i<20;i++)
{ if(i%5==0)
printf("\n");
printf("%d",a[i]);
}
printf("\n");
return 0;
}
```

Example 6.3 the area of ten areas is required to be output from small to large

```#include<stdio.h>
int main()
{
int i,j,t,a[10];
for(i=0;i<10;i++)
scanf("%d",&a[i]);
for(j=0;j<10;j++)
{
for(i=0;i<9-j;i++)
if(a[i]>a[i+1])
{ t=a[i];
a[i]=a[i+1];
a[i+1]=t;
}
}
for(i=0;i<10;i++)
printf("%5d",a[i]);
printf("\n");
return 0;
}
```

Example 6.4 interchange elements of row and column of a two-dimensional array

```#include<stdio.h>
int main()
{
int a[2][3]={1,2,3,4,5,6};
int b[3][2],i,j;
printf("The original array is\n");
for(i=0;i<2;i++)
{ for(j=0;j<3;j++)
{printf("%3d",a[i][j]);
b[j][i]=a[i][j];
}
printf("\n");
}
printf("The array after exchange is\n");
for(i=0;i<3;i++)
{for(j=0;j<2;j++)
printf("%3d",b[i][j]);
printf("\n");
}
return 0;
}
```

Example 6.5 has an array of 3 * 4, which requires the output of the maximum number, as well as its row number and column number

```#include<stdio.h>
int main()
{
int a[3][4]={1,2,3,4,9,8,7,6,-10,10,-5,2},i,j;
int row=0,colum=0,max;
max=a[0][0];
for(i=0;i<3;i++)
{
for(j=0;j<4;j++)
if(a[i][j]>max)
max=a[i][j];
}
printf("%d",max);
printf("row=%d\ncolum=%d\n",row,colum);
return 0;
}
```

Example 6.6 output a known string

```#include<stdio.h>
int main()
{
char c[15]={'I',' ','a','m',' ','a',' ','s','t','u','d','e','n','t','.'};
int i;
for(i=0;i<15;i++)
printf("%d",c[i]);
printf("\n");
return 0;
}
```

Example 6.7 output a diamond

```#include<stdio.h>
int main()
{
char c[][5]={{' ',' ','*'},{' ','*',' ','*'},{'*',' ',' ',' ','*'},{' ','*',' ','*'},{' ',' ','*'}};
int i,j;
for(i=0;i<5;i++)
{for(j=0;j<5;j++)
printf("%c",c[i][j]);
printf("\n");
}
return 0;
}
```

Example 6.8 input a line of characters to determine how many words there are

```int main()
{
int num=0,word=0,i,string[81];
printf("Please enter a line of characters\n");
gets(string);
for(i=0;(c=string[i])!='\0';i++)
{
if(c==' ')  word=0;
else if(word==0)
{num++;word=1;}
}
printf("This string contains%d Word\n",num);
return 0;
}
```

Example 6.9 has three strings, asking for the largest one

```#include<stdio.h>
int main()
{
char str[3][20];
char string[20];
int i;
for(i=0;i<3;i++)
gets(str[i]);
if(strcmp(str[0],str[1])<0)
strcpy(string,str[1]);
else  strcpy(string,str[0]);
if(strcmp(string,str[2])<0)
strcpy(string,str[2]);
printf("Maximum characters are%s\n",string);
return 0;
}
```

Added by 4rxsid on Sun, 24 Nov 2019 19:03:32 +0200