The solution to the accuracy problem of JavaScript floating point arithmetic bignumber.js

The principle of accuracy is described in the previous article. https://my.oschina.net/xiaogg/blog/2998192 Also mentioned some solutions

Today I'm going to talk about a new approach

Is to make use of bignumber.js This plugin. I've applied this plugin to the calculation of grocery shopping

Instance address: http://tool.bitefu.net/jisuan/

Buy food source download: https://www.90pan.com/b1791720 Password: 2e40

Buying food counts as android download: https://www.90pan.com/b1791721 Password: 43vs
bignumber.js download address: https://www.90pan.com/b1791719 Password: r22l

bignumber.js open source address: https://gitee.com/web/bignumber.js

The simple usage is as follows

//Additive function
function accAdd(arg1,arg2){
    var x = new BigNumber(arg1);
    var y = new BigNumber(arg2);
    return x.plus(y);
}
//Subtraction function
function accSub(arg1, arg2) {
    var x = new BigNumber(arg1);
    var y = new BigNumber(arg2);
    return x.minus(y);
}
//Multiplication function
function accMul(arg1, arg2) {
    var x = new BigNumber(arg1);
    var y = new BigNumber(arg2);
    return x.multipliedBy(y);
}
//Division function
function accDiv(arg1, arg2) {    
    var x = new BigNumber(arg1);
    var y = new BigNumber(arg2);
    return x.dividedBy(y);
}

Take a look at the usage documentation

File

Addition plus

  • grammar
    .plus(n [, base])
    • parameter values
      • n (required): number|string|BigNumber the number that participates in the calculation
      • Base: numberary (default is decimal)
    • Return value
      BigNumber
  • Give an example
0.1 + 0.2                       // 0.30000000000000004
x = new BigNumber(0.1)
y = x.plus(0.2)                 // '0.3'
BigNumber(0.7).plus(x).plus(y)  // '1'
x.plus('0.1', 8)                // '0.225'

Subtraction minus

  • grammar
    .minus(n [, base])
    • parameter values
      • n (required): number|string|BigNumber the number that participates in the calculation
      • Base: numberary (default is decimal)
    • Return value
      • BigNumber
  • Give an example
0.3 - 0.1                       // 0.19999999999999998
x = new BigNumber(0.3)
x.minus(0.1)                    // '0.2'
x.minus(0.6, 20)                // '0'

Multiplication multipliedBy

  • grammar
    .times(n [, base])
    • parameter values
      • n (required): number|string|BigNumber the number that participates in the calculation
      • Base: numberary (default is decimal)
    • Return value
      • BigNumber
  • Give an example
0.6 * 3                         // 1.7999999999999998
x = new BigNumber(0.6)
y = x.multipliedBy(3)           // '1.8'
BigNumber('7e+500').times(y)    // '1.26e+501'
x.multipliedBy('-a', 16)        // '-6'

Division dividedBy

  • grammar
    .div(n [, base])
    • parameter values
      • n (required): number|string|BigNumber the number that participates in the calculation
      • Base: numberary (default is decimal)
    • Return value
      • BigNumber
  • Give an example
x = new BigNumber(355)
y = new BigNumber(113)
x.dividedBy(y)                  // '3.14159292035398230088'
x.div(5)                        // '71'
x.div(47, 16)                   // '5'

Division-Rounding DivididedToIntegerBy

  • grammar
    .idiv(n [, base])
    • parameter values
      • n (required): number|string|BigNumber the number that participates in the calculation
      • Base: numberary (default is decimal)
    • Return value
      • BigNumber
  • Give an example
x = new BigNumber(5)
y = new BigNumber(3)
x.dividedToIntegerBy(y)         // '1'
x.idiv(0.7)                     // '7'
x.idiv('0.f', 16)               // '5'

Division-Remaining modulo

  • grammar
    .mod(n [, base])
    • parameter values
      • n (required): number|string|BigNumber the number that participates in the calculation
      • Base: numberary (default is decimal)
    • Return value
      • BigNumber
  • Give an example
1 % 0.9                         // 0.09999999999999998
x = new BigNumber(1)
x.modulo(0.9)                   // '0.1'
y = new BigNumber(33)
y.mod('a', 33)                  // '3'

exponentiatedBy

  • grammar
    .pow(n [, m])
    • parameter values
      • n (required): number|string|BigNumber the number that participates in the calculation
      • m: number|string|BigNumber index
    • Return value
      • BigNumber
  • Give an example
Math.pow(0.7, 2)                // 0.48999999999999994
x = new BigNumber(0.7)
x.exponentiatedBy(2)            // '0.49'
BigNumber(3).pow(-2)            // '0.11111111111111111111'

Square root

  • grammar
    .sqrt()
  • Give an example
x = new BigNumber(16)
x.squareRoot()                  // '4'
y = new BigNumber(3)
y.sqrt()                        // '1.73205080756887729353'

Rounding toFixed

  • grammar
    .toFixed([dp [, rm]])
    • dp (required): number preserves decimal places
    • rm: number
  • Give an example
x = 3.456
y = new BigNumber(x)
x.toFixed()                     // '3'
y.toFixed()                     // '3.456'
y.toFixed(0)                    // '3'
x.toFixed(2)                    // '3.46'
y.toFixed(2)                    // '3.46'
y.toFixed(2, 1)                 // '3.45'  (ROUND_DOWN)
x.toFixed(5)                    // '3.45600'
y.toFixed(5)                    // '3.45600'

Keywords: Programming Android

Added by idnoble on Fri, 03 Apr 2020 19:24:41 +0300