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Find all information about the latest employee
CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`)); --------------------------------- select * from employees order by hire_date desc limit 1
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Find all the information of the employee whose time rank is the third from the bottom
CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`)); ---------------------------------- select * from employees order by hire_date desc limit 1 offset 2(offset:Line number, starting at 0)
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Find the last name and first name of all employees who have assigned departments
CREATE TABLE `dept_emp` ( `emp_no` int(11) NOT NULL, `dept_no` char(4) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`dept_no`)); ---------------------------------- CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`)); ------------------------------------ select last_name,first_name,dept_no from dept_emp join employees on dept_emp.emp_no = employees.emp_no
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Find the last name and first name of all employees and the corresponding department number dept No., including displaying the employees without specific department assignment.
CREATE TABLE `dept_emp` ( `emp_no` int(11) NOT NULL, `dept_no` char(4) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`dept_no`)); CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`)); --------------------------------- select last_name,first_name,dept_no from employees left join dept_emp on dept_emp.emp_no = employees.emp_no
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Find the salary of all employees at the time of entry, give EMP no and salary, and reverse the order according to EMP No.
CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name` varchar(14) NOT NULL, `last_name` varchar(16) NOT NULL, `gender` char(1) NOT NULL, `hire_date` date NOT NULL, PRIMARY KEY (`emp_no`)); CREATE TABLE `salaries` ( `emp_no` int(11) NOT NULL, `salary` int(11) NOT NULL, `from_date` date NOT NULL, `to_date` date NOT NULL, PRIMARY KEY (`emp_no`,`from_date`)); --------------------------------- select e.emp_no,salary from employees e left join salaries s on e.emp_no = s.emp_no and e.hire_date = s.from_date order by e.emp_no desc
Five MySQL channels a day --- 1
Added by ghe on Thu, 31 Oct 2019 22:24:00 +0200