Simulate spring boot to write a tool class nested Tomcat (easy to debug)

In order to debug the SpringMVC code in the Spring source project, using Tomcat plug-in is more convenient, then you need to simulate the function of SpringBoot like yourself: start the Spring application, embedded Tomcat and do a good job of correlation.

Why is it so troublesome??? Because I am a common Java project, the basic web.xml file, I need to write code to add Context\Servlet to Tomcat and bind with Spring web context.

To fully understand this part of the code, you need to have a deeper understanding of Tomcat and Spring. You can take a look at the previous Spring and Tomcat source code analysis

First, create a new normal Java project in the Spring project. Note that it is built with Gradle

Other steps are omitted and only build.gradle file is pasted

plugins {
    id 'java'

group 'org.springframework'
version '5.2.0.BUILD-SNAPSHOT'

sourceCompatibility = 1.8

dependencies {
    compile project(":spring-context")
    compile project(":spring-webmvc")
    testCompile group: 'junit', name: 'junit', version: '4.12'
    compile group: 'org.apache.tomcat.embed', name: 'tomcat-embed-core', version: '8.5.49'
    compile group: 'org.projectlombok', name: 'lombok', version: '1.18.10'
    compile group: 'com.fasterxml.jackson.core', name: 'jackson-databind', version: '2.9.8'
    compile group: 'com.fasterxml.jackson.core', name: 'jackson-core', version: '2.9.8'

Why to import jackson's stuff, because I want to convert the object returned by the Controller to json string output

Upper Code:

Simulate spring boot with Tomcat container

public class WebMvcMain{
	public static void main(String[] args) {
		try {
			//Instantiate a Spring web context
			AnnotationConfigWebApplicationContext ac = new AnnotationConfigWebApplicationContext();

			//Instantiating Spring's DispatcherServlet DispatcherServlet and context binding
			DispatcherServlet dispatcherServlet = new DispatcherServlet(ac);

			//Instantiate Tomcat
			Tomcat tomcat = new Tomcat();

			//Tomcat add Servlet
			Context context = tomcat.addContext("/", "f:\\data\\spring-tomcat\\app");
			Tomcat.addServlet(context, "st", dispatcherServlet);
			context.addServletMapping("/", "st");

			//Start Tomcat
		}catch (Exception e){

The following class is to complete the HTTPMessageConverter registration (some friends may ask why not rewrite its methods with the WebMvcConfigure interface to complete the custom Converter addition...)... I guess it's because I can't use @ EnableWebMvc)

public class MyHttpMessageConverterProcessor implements BeanPostProcessor{
	public Object postProcessAfterInitialization(Object bean, String beanName) throws BeansException {
			List<HttpMessageConverter<?>> messageConverters = ((RequestMappingHandlerAdapter) bean).getMessageConverters();
			messageConverters.add(new MappingJackson2HttpMessageConverter());
		return bean;

User object

public class User {
	public User(){}

	public User(String userName,Integer age){
		this.userName = userName;
		this.age = age;
	private String userName;
	private Integer age;


public class UserController {
	private User user = new User("Messi",33);

	public User queryAllUser(){
		return user;

Note that all other classes to be scanned must be in the com.jv.webmvc directory and its subdirectories


Complete the above code and start the spring MVC application

Tomcat started successfully

Browser access: http://localhost:8080/user

Keywords: Programming Tomcat Spring Java Gradle

Added by Zallus on Thu, 12 Dec 2019 18:03:17 +0200