characters will have many problems. Record them and find them for a long time. It turns out that they are the problem of spaces. Here is the xml file after format and the corresponding print

xml file:

Corresponding log:

Reference: the following excerpt from http://blog.csdn.net/Garmiter/article/details/8016840

XML type 1: no space left

1. <?xml version="1.0" encoding="utf-8"?>  
2. <workers>  
3. <worker id="1001">  
4. <name>Garmiter</name>  
5. <sex>Boy</sex>  
6. <address>Sichuan Province,Chengdu City</address>  
7. <money>$2345678</money>  
8. <status>001</status>  
9. </worker>  
10. <worker id="1002">  
11. <name>Garmiter2</name>  
12. <sex>Boy2</sex>  
13. <address>Sichuan Province,Chengdu City</address>  
14. <money>$23456782</money>  
15. <status>002</status>  
16. </worker>  
17. </workers>  

XML type 2: space on the left

1. <?xml version="1.0" encoding="utf-8"?>  
2. <workers>  
3.   <worker id="1001">  
4.     <name>Garmiter</name>  
5.     <sex>Boy</sex>  
6.     <address>Sichuan Province,Chengdu City</address>  
7.     <money>$2345678</money>  
8.     <status>001</status>  
9.   </worker>  
10.   <worker id="1002">  
11.     <name>Garmiter2</name>  
12.     <sex>Boy2</sex>  
13.     <address>Sichuan Province,Chengdu City</address>  
14.     <money>$23456782</money>  
15.     <status>002</status>  
16.   </worker>  
17. </workers>  

android parses XML fragment code - type 1: execute the above XML types only once, execute the above XML types twice and affect the result

1. @Override  
2.     public void characters(char[] ch, int start, int length)  
3.             throws SAXException {  
4.         //System.out.println("-----------tagname="+tagname);  
5.         if(tagname.equals("name")){  
6.             hisname=new String(ch,start,length);  
7.             System.out.println("===="+hisname);  
8.         }else if(tagname.equals("sex")){  
9.             sex=new String(ch,start,length);   
10.             System.out.println("===="+sex);  
11.         }else if(tagname.equals("address")){  
12.             address=new String(ch,start,length);   
13.             System.out.println("===="+address);  
14.         }else if(tagname.equals("money")){  
15.             money=new String(ch,start,length);   
16.             System.out.println("===="+money);  
17.         }else if(tagname.equals("status")){  
18.             status=new String(ch,start,length);   
19.             System.out.println("===="+status);  
20.         }  
21.           
22.     }  

android parsing XML fragment code - type 2: execute the above XML types only once, and execute the above XML types twice without affecting the result

1. @Override  
2.     public void characters(char[] ch, int start, int length)  
3.             throws SAXException {  
4.         //System.out.println("-----------tagname="+tagname);  
5.         if(tagname.equals("name")){  
6.             hisname=new String(ch,start,length);  
7.             System.out.println("===="+hisname);  
8.         }else if(tagname.equals("sex")){  
9.             sex=new String(ch,start,length);   
10.             System.out.println("===="+sex);  
11.         }else if(tagname.equals("address")){  
12.             address=new String(ch,start,length);   
13.             System.out.println("===="+address);  
14.         }else if(tagname.equals("money")){  
15.             money=new String(ch,start,length);   
16.             System.out.println("===="+money);  
17.         }else if(tagname.equals("status")){  
18.             status=new String(ch,start,length);   
19.             System.out.println("===="+status);  
20.         }  
21.         tagname="";//Give tagname to not meet any of the above conditions, so that no valid steps will be taken for multiple executions  
22.     }